How To Calculate FUWUKARI Post UTME/Aggregate Score For All Courses

Many Students find it hard to calculate their aggregate score and their cut off mark as this varies for different Institutions, but before this, we are going to tell you what aggregate and Post UTME Score means and what things are to be considered before calculating the aggregate score.


That means the candidate must get at least 50 Questions Correctly. The aggregate score will be used to determine the cut-off point for admission into each of the programmes. Cut-off points for each course will be determined by the performance of all the candidates who applied for the course.

See: List of Nigerian Universities That Accepts 120 As Cut Off Mark 


After every UTME exercise, a particular mark is set out by the exam body {e.g 120}. This mark is a score a candidate must have or cross, to qualify him or her to sit for the chosen school’s POST UTME exercise. This said mark is announced to all school’s to enable them decide the number of candidates they will admit.
After the school’s decision, they announce a particular mark which must not be lower than the mark the UTME body fixed. Any candidate who cross the mark set by the UTME body and did not reach the chosen school’s mark, is NEVER eligible to sit for the school’s POST UTME.
This mark or score set by the school admission board is known as SCHOOL’S CUT OFF MARK..

Also see: Easiest Ways of Getting Admission into 200 L in Nigerian Universities 


When calculating FUWUKARI  aggregate score, three areas are considered. they are;

  1. O’LEVEL

A1 – 6

B2- 5





And maximum is 30 points, then split to 20 through multiplication by 2/3.

2. Post UTME 

The Post UTME is split to 30 marks using 0.3 as the multiplier.


The candidates JAMB score will be divided into 8

For a better understanding, lets use Treasure as a case study.

Assume Treasure score 250, her score will be 250/2= 31.25

Maths B2-5, English A1-6, Biology B2-5, Physics C4-3, Chemistry A1-6, Total gross points for O’Level is = 25, the score is then multiplied by 2/3 ie 25 x 2/3= 16.7. She score 55 in her Post UTME and it is multiplied by 0.3 ie 55 x 0.3= 16.5

Therefore, Treasure’s aggregate score is the sum of the the three scores ie JAMB + O’Level + Post UTME which is 31.25 + 16.7 + 16.5= 64.45 .

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